integral of 2+1/x

Lösung

\int 2 + \frac{1}{x} d x

2 x + ln ∣ x ∣ + C

Schritte zur Lösung

\int 2 + \frac{1}{x} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 d x + \int \frac{1}{x} d x

\int 2 d x = 2 x

\int \frac{1}{x} d x = ln ∣ x ∣

= 2 x + ln ∣ x ∣

Füge eine Konstante zur Lösung hinzu

= 2 x + ln ∣ x ∣ + C

t an g e n t f (x) = \frac{- 8 x}{x ^{2} + 1}, at x = 1

\frac{\partial}{\partial x} (2 x^{2} y + 4)

s l o p e (0, 2), (1, 0)

in v erse l a pl a ce \frac{4 s e ^{- 2 s}}{3 s ^{2} + 12}

\frac{d y}{d t} = y + 2 sin (t) + 1