derivative t^3-1/(\sqrt[4]{t^7)}

Lösung

ableitung von

t^{3} - \frac{1}{4 t ^{7}}

3 t^{2} + \frac{7 t ^{6}}{4 ( t ^{7} ) ^{\frac{5}{4}}}

Schritte zur Lösung

\frac{d}{d t} (t^{3} - \frac{1}{4 t ^{7}})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{3}) - \frac{d}{d t} (\frac{1}{4 t ^{7}})

\frac{d}{d t} (t^{3}) = 3 t^{2}

\frac{d}{d t} (\frac{1}{4 t ^{7}}) = - \frac{7 t ^{6}}{4 ( t ^{7} ) ^{\frac{5}{4}}}

= 3 t^{2} - (- \frac{7 t ^{6}}{4 ( t ^{7} ) ^{\frac{5}{4}}})

Vereinfache

= 3 t^{2} + \frac{7 t ^{6}}{4 ( t ^{7} ) ^{\frac{5}{4}}}

t an g e n t f (x) = \frac{1}{x - 1}, at x = 2

in v erse l a pl a ce \frac{1}{s ( s + 8 )}

\int x^{x} (1 + ln (x)) d x

d er i v a t i v e \frac{x ^{4} + 9}{x ^{2}}

\frac{d x}{d t} = 2 (2 x t)