derivative f(x)=sqrt(3x+1)

Lösung

ableitung von

f (x) = 3 x + 1

\frac{3}{2 3 x + 1}

Schritte zur Lösung

\frac{d}{d x} (3 x + 1)

Wende die Kettenregel an:

\frac{1}{2 3 x + 1} \frac{d}{d x} (3 x + 1)

= \frac{1}{2 3 x + 1} \frac{d}{d x} (3 x + 1)

\frac{d}{d x} (3 x + 1) = 3

= \frac{1}{2 3 x + 1} \cdot 3

Vereinfache

\frac{1}{2 3 x + 1} \cdot 3 : \frac{3}{2 3 x + 1}

= \frac{3}{2 3 x + 1}

\frac{\partial}{\partial x} (10)

\frac{\partial}{\partial y} (x^{2} + 2 y^{2} + 3 x z)

x \to - 2 lim (\frac{1}{x + 1})

\int \frac{4}{x ln ( 5 x )} d x

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