(e^{-y}+1)sin(x)dx=(1+cos(x))dy,y(0)=0

解答

(e^{- y} + 1) sin (x) d x = (1 + cos (x)) d y, y (0) = 0

0

求解步骤

给定

(e^{- y} + 1) sin (x) d x (x, y) = (1 + cos (x)) d y, y (0) = 0

找到

(e^{- y} + 1) sin (x) d x \circ y (0)

乘开

(e^{- y} + 1) sin (x) d x \circ y \cdot 0 : 0

= 0

\int p (p + 1)^{5} d p

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