integral from-1 to 1 of ln|x|

Lösung

\int_{- 1}^{1} ln ∣ x ∣ d x

- 2

Schritte zur Lösung

\int_{- 1}^{1} ln ∣ x ∣ d x

Entferne die Extremwerte

= \int_{- 1}^{0} ln (- x) d x + \int_{0}^{1} ln (x) d x

\int_{- 1}^{0} ln (- x) d x = - 1

\int_{0}^{1} ln (x) d x = - 1

= - 1 - 1

Vereinfache

= - 2

a re a y = \frac{13}{x ^{2} + 5 x + 6}, y = 0, x = 0, x = 1

12 y^{^{''}} - 12 y^{^{'}} + 78 y = 0

\int 5 e^{- 0.5 x} d x

\frac{d}{d x} (65 - 55 cos (\frac{π x}{15}))

\frac{\partial}{\partial x} (\frac{x ^{2} + 4}{y - 3})