(\partial)/(\partial x)((F(c,x,b)cos(c))/(xb))

Lösung

\frac{\partial}{\partial x} (\frac{F ( c , x , b ) \cdot cos ( c )}{x \cdot b})

\frac{cos ( c )}{b} \cdot \frac{\frac{\partial}{\partial x} ( F ( c , x , b ) ) x - 1 \cdot F ( c , x , b )}{x ^{2}}

Schritte zur Lösung

\frac{\partial}{\partial x} (\frac{F ( c , x , b ) cos ( c )}{x b})

Behandle

c, b

als Konstanten

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{cos ( c )}{b} \frac{\partial}{\partial x} (\frac{F ( c , x , b )}{x})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{cos ( c )}{b} \cdot \frac{\frac{\partial}{\partial x} ( F ( c , x , b ) ) x - \frac{\partial}{\partial x} ( x ) F ( c , x , b )}{x ^{2}}

\frac{\partial}{\partial x} (x) = 1

= \frac{cos ( c )}{b} \cdot \frac{\frac{\partial}{\partial x} ( F ( c , x , b ) ) x - 1 \cdot F ( c , x , b )}{x ^{2}}

\frac{d}{d x} (sin (2 cos (x)))

\frac{d}{d x} (\frac{4 x ^{5}}{( 2 x ^{3} - 2 ) ^{3}})

x \to 0 - lim (\frac{1}{x} \cdot e^{\frac{1}{x}})

\frac{d}{d x} (2 x + 3 - x)

\frac{d}{d y} (x - 5 ln ∣ x ∣ + y x)