d/(dθ)(5sin(2θ))

Lösung

\frac{d}{d θ} (5 sin (2 θ))

10 cos (2 θ)

Schritte zur Lösung

\frac{d}{d θ} (5 sin (2 θ))

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d θ} (sin (2 θ))

Wende die Kettenregel an:

cos (2 θ) \frac{d}{d θ} (2 θ)

= cos (2 θ) \frac{d}{d θ} (2 θ)

\frac{d}{d θ} (2 θ) = 2

= 5 cos (2 θ) \cdot 2

Vereinfache

= 10 cos (2 θ)

y^{^{''}} + 3 y = 0

\int \frac{x ^{2} + 2 x + 3}{x ^{3} - x} d x

\int_{2}^{3} \frac{1}{x - 1} d x

x \to - 4 lim (6 x + 11)

\frac{d}{d x} (x^{2} \cdot tan (\frac{1}{x}))