integral of (1+sin(x))

Lösung

\int (1 + sin (x)) d x

x - cos (x) + C

Schritte zur Lösung

\int 1 + sin (x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d x + \int sin (x) d x

\int 1 d x = x

\int sin (x) d x = - cos (x)

= x - cos (x)

Füge eine Konstante zur Lösung hinzu

= x - cos (x) + C

\frac{\partial}{\partial x} (2 x^{2} - 3 y^{2} - 2 x)

\int tan (\frac{x}{2}) d x

\frac{d}{d t} (t cos (6 t))

\frac{\partial}{\partial x} (e^{2 x^{3} - 3 y})

\int \frac{x ^{2} - 8 x - 1}{( x - 1 ) ^{2} ( x ^{2} + 1 )} d x