derivative x^3-2x^2+4x+3

Lösung

ableitung von

x^{3} - 2 x^{2} + 4 x + 3

3 x^{2} - 4 x + 4

Schritte zur Lösung

\frac{d}{d x} (x^{3} - 2 x^{2} + 4 x + 3)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (3)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3) = 0

= 3 x^{2} - 4 x + 4 + 0

Vereinfache

= 3 x^{2} - 4 x + 4

\frac{\partial}{\partial x} (ln (x^{2} + y^{4} + 2))

n = 1 \sum \infty \frac{n}{n ^{2} + 2}

\frac{d}{d x} (- 8 sin (\frac{3 x}{2} + 1))

x \to 4 - lim (2 x - 1)

t an g e n t f (x) = \frac{( x - 4 )}{x - 2}