derivative h(t)=-16t^2+144t

解答

导数

h (t) = - 16 t^{2} + 144 t

- 32 t + 144

求解步骤

\frac{d}{d t} (- 16 t^{2} + 144 t)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (16 t^{2}) + \frac{d}{d t} (144 t)

\frac{d}{d t} (16 t^{2}) = 32 t

\frac{d}{d t} (144 t) = 144

= - 32 t + 144

d er i v a t i v e 30 e^{- 0.0000323 h}

x \to 0 lim (- 2 x sin (\frac{1}{x}))

\frac{\partial}{\partial y} (x y^{2} - 6 x^{2} - 3 y^{2})

d er i v a t i v e y = (8 x^{3} + 5)^{\frac{3}{2}}

a re a y = e^{x}, y = e^{- 2 x}, x = ln (6)