f^{''}(x)= 1/x

Lösung

f^{^{''}} (x) = \frac{1}{x}

f (x) = x (ln (x) + c_{1}) - x + c_{2}

Schritte zur Lösung

f^{''} (x) = \frac{1}{x}

Löse

f^{''} (x) = \frac{1}{x} : f^{'} (x) = ln (x) + c_{1}

Löse

f^{'} (x) = ln (x) + c_{1} : f (x) = x (ln (x) + c_{1}) - x + c_{2}

f (x) = x (ln (x) + c_{1}) - x + c_{2}

y^{^{''}} - 4 y^{^{'}} + 20 y = 0, y (0) = - 1, y^{^{'}} (0) = - 3

\int_{10}^{20} \frac{10}{x ^{2}} d x

\int 4 x^{2} (4 x^{3} - x^{2})^{6} d x

y^{^{''}} + y^{^{'}} - 6 y = t e^{2 t}

\frac{\partial}{\partial x} (1 + \frac{2}{y})