9y^{''}-6y^'+4y=0

Lösung

9 y^{^{''}} - 6 y^{^{'}} + 4 y = 0

y = e^{\frac{t}{3}} (c_{1} cos (\frac{t}{3}) + c_{2} sin (\frac{t}{3}))

Schritte zur Lösung

9 y^{''} (t) - 6 y^{'} (t) + 4 y = 0

Solve linear ODE:

y = e^{\frac{t}{3}} (c_{1} cos (\frac{t}{3}) + c_{2} sin (\frac{t}{3}))

y = e^{\frac{t}{3}} (c_{1} cos (\frac{t}{3}) + c_{2} sin (\frac{t}{3}))

\frac{d}{d x} ((1 - x) e^{- x})

x \to 0 lim (\frac{4 sin ( 3 x )}{2 tan ( 5 x )})

x \to 1 lim (\frac{( x ^{2} )}{x - 1})

\int_{0}^{1} \frac{3 x ^{2}}{1 + x ^{3}} d x

x^{2} y^{^{''}} - 3 x y^{^{'}} + 5 y = 0