(6xy-2y^2+1)dx+(3x^2-4xy)dy=0

Lösung

(6 x y - 2 y^{2} + 1) d x + (3 x^{2} - 4 x y) d y = 0

y = - \frac{- 3 x ^{2} + 9 x ^{4} + 8 x ( x - c _{1} )}{4 x}, y = - \frac{- 3 x ^{2} - 9 x ^{4} + 8 x ( x - c _{1} )}{4 x}

Schritte zur Lösung

(6 x y - 2 y^{2} + 1) d x + (3 x^{2} - 4 x y) d y = 0

Solve exact ODE:

y = - \frac{- 3 x ^{2} + 9 x ^{4} + 8 x ( x - c _{1} )}{4 x}, y = - \frac{- 3 x ^{2} - 9 x ^{4} + 8 x ( x - c _{1} )}{4 x}

y = - \frac{- 3 x ^{2} + 9 x ^{4} + 8 x ( x - c _{1} )}{4 x}, y = - \frac{- 3 x ^{2} - 9 x ^{4} + 8 x ( x - c _{1} )}{4 x}

\int \frac{5}{6 x + 5} d x

d er i v a t i v e \frac{x}{7 x ^{2} + 1}

d er i v a t i v e f (x) = e^{2 e^{x}}

\frac{d}{d x} (e^{x} (a cos (x) + b sin (x)))

t an g e n t y = x^{2} - 4 x + 3, (1, 0)