16y^{''}+8y^'+y=x+6

Lösung

16 y^{^{''}} + 8 y^{^{'}} + y = x + 6

y = c_{1} e^{- \frac{x}{4}} + c_{2} e^{- \frac{x}{4}} x + x - 2

Schritte zur Lösung

16 y^{''} (x) + 8 y^{'} (x) + y = x + 6

Solve linear ODE:

y = c_{1} e^{- \frac{x}{4}} + c_{2} e^{- \frac{x}{4}} x + x - 2

y = c_{1} e^{- \frac{x}{4}} + c_{2} e^{- \frac{x}{4}} x + x - 2

y (x + 5) + y^{^{'}} = 0

n = 1 \sum \infty \frac{x ^{n}}{n ^{n}}

x \to 0 lim (- (\frac{1}{x}))

\frac{\partial}{\partial x} (\frac{0.09 ( 5 ^{x} )}{x ^{3}})

\frac{d ^{2}}{d x ^{2}} (sin (x^{3}))