y^{''}+ay+b=0

Lösung

y^{^{''}} + a y + b = 0

y = c_{1} cos (a t) + c_{2} sin (a t) - \frac{b}{a}

Schritte zur Lösung

y^{''} (t) + a y + b = 0

Solve linear ODE:

y = c_{1} cos (a t) + c_{2} sin (a t) - \frac{b}{a}

y = c_{1} cos (a t) + c_{2} sin (a t) - \frac{b}{a}

\frac{d}{d x} (x y^{2} - y^{3})

n = 1 \sum \infty \frac{sin ( \frac{1}{n} )}{n}

n = 1 \sum \infty 4^{n + 1}

n = 1 \sum \infty \frac{1}{n ^{2} + 6 n}

y^{^{''}} + 4 \cdot y = 3 \cdot x - 1