derivative f(x)=9-4/(x^2)

Lösung

ableitung von

f (x) = 9 - \frac{4}{x ^{2}}

\frac{8}{x ^{3}}

Schritte zur Lösung

\frac{d}{d x} (9 - \frac{4}{x ^{2}})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9) - \frac{d}{d x} (\frac{4}{x ^{2}})

\frac{d}{d x} (9) = 0

\frac{d}{d x} (\frac{4}{x ^{2}}) = - \frac{8}{x ^{3}}

= 0 - (- \frac{8}{x ^{3}})

Vereinfache

= \frac{8}{x ^{3}}

\frac{d}{d x} (x^{2} sec (\frac{1}{x}))

\int x^{3.4} - 2 x^{2 - 1} d x

\int_{- 2}^{0} 4 - x^{2} d x

\int x^{3} sin (x) d x

\frac{\partial}{\partial t} (t^{4} e^{- x})