(\partial)/(\partial y)(y-ln(x^2+y^2))

Lösung

\frac{\partial}{\partial y} (y - ln (x^{2} + y^{2}))

1 - \frac{2 y}{x ^{2} + y ^{2}}

Schritte zur Lösung

\frac{\partial}{\partial y} (y - ln (x^{2} + y^{2}))

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y) - \frac{\partial}{\partial y} (ln (x^{2} + y^{2}))

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (ln (x^{2} + y^{2})) = \frac{2 y}{x ^{2} + y ^{2}}

= 1 - \frac{2 y}{x ^{2} + y ^{2}}

d er i v a t i v e y = \frac{3}{x ^{2} - 1}

x \to 0 + lim (6 (cot (x) - \frac{1}{x}))

\frac{d}{d x} (- e^{- 2 x})

t an g e n t f (x) = 5 x + 4, at x = 9

y^{^{''}} + 10 y^{^{'}} + 25 y = 2 r^{- 5 x}