integral of u+1

Lösung

\int u + 1 d u

\frac{u ^{2}}{2} + u + C

Schritte zur Lösung

\int u + 1 d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u d u + \int 1 d u

\int u d u = \frac{u ^{2}}{2}

\int 1 d u = u

= \frac{u ^{2}}{2} + u

Füge eine Konstante zur Lösung hinzu

= \frac{u ^{2}}{2} + u + C

y = sec (1 + 3 4 + arcsin (4 + π^{2}))

10 (t + 1) \frac{d y}{d t} - 9 y = 9 t

x \to 0 lim (\frac{- cos ( x ) + 1}{x})

\frac{d}{d x} (\frac{x - 5}{( x - 3 ) ( x - 1 )})

\int sin^{5} (\frac{x}{3}) cos (\frac{x}{3}) d x