integral from-1 to 3 of |x-2|

Lösung

\int_{- 1}^{3} ∣ x - 2 ∣ d x

5

Schritte zur Lösung

\int_{- 1}^{3} ∣ x - 2 ∣ d x

Entferne die Extremwerte

= \int_{- 1}^{2} - x + 2 d x + \int_{2}^{3} x - 2 d x

\int_{- 1}^{2} - x + 2 d x = \frac{9}{2}

\int_{2}^{3} x - 2 d x = \frac{1}{2}

= \frac{9}{2} + \frac{1}{2}

Vereinfache

\frac{9}{2} + \frac{1}{2} : 5

= 5

\frac{\partial}{\partial y} (2 x^{4} y z^{3})

d er i v a t i v e cos (2 x)

\frac{d}{d x} (\frac{x y}{x ^{2} + y ^{2} + z ^{2}})

\frac{d y}{d x} = a y - b y^{2}

l a pl a ce t r an s f or m 8 sin (4 t) - 5 cos (4 t)