6x^2y^'=y^'+2xe^{-y}

Lösung

6 x^{2} y^{^{'}} = y^{^{'}} + 2 x e^{- y}

y = ln (\frac{1}{6} ln (6 x^{2} - 1) + c_{1})

Schritte zur Lösung

6 x^{2} y^{'} (x) = y^{'} (x) + 2 x e^{- y}

Solve separable ODE:

y = ln (\frac{1}{6} ln (6 x^{2} - 1) + c_{1})

y = ln (\frac{1}{6} ln (6 x^{2} - 1) + c_{1})

\frac{\partial}{\partial x} (x^{3} cos (y))

\int 1 - t^{2} d t

\frac{\partial}{\partial y} (4 x y - x^{4} - y^{4})

\frac{\partial}{\partial x} \frac{U ( x , y )}{( 1 + \frac{x}{y} ) ^{2}}

x \to 0 lim ((1 + 5 x)^{\frac{1}{x}})