(2y+2t-7)dt+(4y+2t-1)dy=0,y(-1)=2

Lösung

(2 y + 2 t - 7) d t + (4 y + 2 t - 1) d y = 0, y (- 1) = 2

y = \frac{1 - 2 t + - 4 t ^{2} + 52 t + c _{1} + 1}{4}, y = \frac{1 - 2 t - - 4 t ^{2} + 52 t + c _{1} + 1}{4}

Schritte zur Lösung

(2 y + 2 t - 7) d t + (4 y + 2 t - 1) d y = 0

Solve exact ODE:

y = \frac{1 - 2 t + - 4 t ^{2} + 52 t + c _{1} + 1}{4}, y = \frac{1 - 2 t - - 4 t ^{2} + 52 t + c _{1} + 1}{4}

y = \frac{1 - 2 t + - 4 t ^{2} + 52 t + c _{1} + 1}{4}, y = \frac{1 - 2 t - - 4 t ^{2} + 52 t + c _{1} + 1}{4}

d er i v a t i v e f (x) = 2 x - 3

d er i v a t i v e f (x) = (1 + 3 x^{4})^{2} + 3 x^{3}

y^{^{''}} + y^{^{'}} + 2 y = 0, y (0) = 2, y^{^{'}} (0) = 0

in v erse l a pl a ce \frac{8}{s ^{2} + 1}

\frac{1}{y} d y = \frac{x + 1}{1 - x ^{2}} d x