derivative of sqrt(8x+1)

Lösung

\frac{d}{d x} (8 x + 1)

\frac{4}{8 x + 1}

Schritte zur Lösung

\frac{d}{d x} (8 x + 1)

Wende die Kettenregel an:

\frac{1}{2 8 x + 1} \frac{d}{d x} (8 x + 1)

= \frac{1}{2 8 x + 1} \frac{d}{d x} (8 x + 1)

\frac{d}{d x} (8 x + 1) = 8

= \frac{1}{2 8 x + 1} \cdot 8

Vereinfache

\frac{1}{2 8 x + 1} \cdot 8 : \frac{4}{8 x + 1}

= \frac{4}{8 x + 1}

\int_{0}^{2} (x + 2)^{2} d x

\frac{d}{d x} (sinh (ln (x)))

x \to 1 - lim (\frac{x - 1}{x + 1})

f (x) = \frac{x}{10}

x \to \infty lim (\frac{1}{x} - 4)