integral from 3 to 4 of y^3+1/(4y^3)

Lösung

\int_{3}^{4} y^{3} + \frac{1}{4 y ^{3}} d y

\frac{50407}{1152}

Dezimale

43.75607 \dots

Schritte zur Lösung

\int_{3}^{4} y^{3} + \frac{1}{4 y ^{3}} d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{3}^{4} y^{3} d y + \int_{3}^{4} \frac{1}{4 y ^{3}} d y

\int_{3}^{4} y^{3} d y = \frac{175}{4}

\int_{3}^{4} \frac{1}{4 y ^{3}} d y = \frac{7}{1152}

= \frac{175}{4} + \frac{7}{1152}

Vereinfache

\frac{175}{4} + \frac{7}{1152} : \frac{50407}{1152}

= \frac{50407}{1152}

f (x) = sin (7 ln (x))

\frac{d}{d x} (cos (3 cos (2 x)))

l a pl a ce t r an s f or m e^{- 2 s}

f^{^{'}} (x) = - \frac{1}{x} (f (x))

in v erse l a pl a ce \frac{s + 1}{s ^{2} + 2 s + 2}