integral of 8x+6

Lösung

\int 8 x + 6 d x

4 x^{2} + 6 x + C

Schritte zur Lösung

\int 8 x + 6 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 8 x d x + \int 6 d x

\int 8 x d x = 4 x^{2}

\int 6 d x = 6 x

= 4 x^{2} + 6 x

Füge eine Konstante zur Lösung hinzu

= 4 x^{2} + 6 x + C

\int 8 cos^{3} (2 θ) sin (2 θ) d θ

d er i v a t i v e (\frac{1}{y ^{2}} - \frac{7}{y ^{4}}) (y + 5 y^{3})

x \to 2 - lim (cos (\frac{1}{x - 2}))

\frac{d}{d x} (x^{3} e^{- 8 x})

\frac{\partial}{\partial x} (x \cdot cos (π \cdot x \cdot y^{2}))