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Beliebt Rechnen >

integral of 7ln(x^2-x+8)

Lösung

\int 7 ln (x^{2} - x + 8) d x

Lösung

7 (x ln (x^{2} - x + 8) - \frac{1}{2} ln (x^{2} - x + 8) + 31 arctan (\frac{1}{31} (2 x - 1)) - 2 x + 1) + C

Schritte zur Lösung

\int 7 ln (x^{2} - x + 8) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int ln (x^{2} - x + 8) d x

Vervollständige das Quadrat

x^{2} - x + 8 : (x - \frac{1}{2})^{2} + \frac{31}{4}

= 7 \cdot \int ln ((x - \frac{1}{2})^{2} + \frac{31}{4}) d x

Wende U-Substitution an

= 7 \cdot \int ln (u^{2} + \frac{31}{4}) d u

Wende die partielle Integration an

= 7 (u ln (u^{2} + \frac{31}{4}) - \int \frac{8 u ^{2}}{4 u ^{2} + 31} d u)

\int \frac{8 u ^{2}}{4 u ^{2} + 31} d u = - 31 arctan (\frac{2}{31} u) + 2 u

= 7 (u ln (u^{2} + \frac{31}{4}) - (- 31 arctan (\frac{2}{31} u) + 2 u))

Setze in

u = x - \frac{1}{2}

ein

= 7 ((x - \frac{1}{2}) ln ((x - \frac{1}{2})^{2} + \frac{31}{4}) - (- 31 arctan (\frac{2}{31} (x - \frac{1}{2})) + 2 (x - \frac{1}{2})))

Vereinfache

7 ((x - \frac{1}{2}) ln ((x - \frac{1}{2})^{2} + \frac{31}{4}) - (- 31 arctan (\frac{2}{31} (x - \frac{1}{2})) + 2 (x - \frac{1}{2}))) : 7 (x ln (x^{2} - x + 8) - \frac{1}{2} ln (x^{2} - x + 8) + 31 arctan (\frac{1}{31} (2 x - 1)) - 2 x + 1)

= 7 (x ln (x^{2} - x + 8) - \frac{1}{2} ln (x^{2} - x + 8) + 31 arctan (\frac{1}{31} (2 x - 1)) - 2 x + 1)

Füge eine Konstante zur Lösung hinzu

= 7 (x ln (x^{2} - x + 8) - \frac{1}{2} ln (x^{2} - x + 8) + 31 arctan (\frac{1}{31} (2 x - 1)) - 2 x + 1) + C

Graph

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