1-y^'=cos(y)

Lösung

1 - y^{^{'}} = cos (y)

y = 2 arccot (- t - c_{1}) + 2 πn

Schritte zur Lösung

1 - y^{'} (t) = cos (y)

Solve separable ODE:

y = 2 arccot (- t - c_{1}) + 2 πn

y = 2 arccot (- t - c_{1}) + 2 πn

\int_{2}^{3} \frac{3}{3 - x} d x

a re a x = 0, y = - 1 + \frac{x ^{2}}{4}, y = 2 + \frac{x}{4}

\frac{\partial}{\partial x} (- 45 x y - 5 x^{2} y - 5 x y^{2})

d er i v a t i v e - x^{2} + 12 x - 32

x \to - 2 lim (∣ x - 2 ∣)