(\partial)/(\partial x)(cos(5x-2y^2))

解

\frac{\partial}{\partial x} (cos (5 x - 2 y^{2}))

- sin (5 x - 2 y^{2}) \cdot 5

解答ステップ

\frac{\partial}{\partial x} (cos (5 x - 2 y^{2}))

y

を定数として扱う

連鎖法則を適用:

- sin (5 x - 2 y^{2}) \frac{\partial}{\partial x} (5 x - 2 y^{2})

= - sin (5 x - 2 y^{2}) \frac{\partial}{\partial x} (5 x - 2 y^{2})

\frac{\partial}{\partial x} (5 x - 2 y^{2}) = 5

= - sin (5 x - 2 y^{2}) \cdot 5