(2y^2+3xy-2y+6x)dx+x(x+2y-1)dy=0

解答

(2 y^{2} + 3 x y - 2 y + 6 x) d x + x (x + 2 y - 1) d y = 0

y = \frac{x - x ^{2} + x ^{4} - 10 x ^{3} + x ^{2} + c _{1}}{2 x}, y = \frac{x - x ^{2} - x ^{4} - 10 x ^{3} + x ^{2} + c _{1}}{2 x}

求解步骤

(2 y^{2} + 3 x y - 2 y + 6 x) d x + x (x + 2 y - 1) d y = 0

求解恰当方程:

y = \frac{x - x ^{2} + x ^{4} - 10 x ^{3} + x ^{2} + c _{1}}{2 x}, y = \frac{x - x ^{2} - x ^{4} - 10 x ^{3} + x ^{2} + c _{1}}{2 x}

y = \frac{x - x ^{2} + x ^{4} - 10 x ^{3} + x ^{2} + c _{1}}{2 x}, y = \frac{x - x ^{2} - x ^{4} - 10 x ^{3} + x ^{2} + c _{1}}{2 x}

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