integral of 4+6x+36x^2

Lösung

\int 4 + 6 x + 36 x^{2} d x

4 x + 3 x^{2} + 12 x^{3} + C

Schritte zur Lösung

\int 4 + 6 x + 36 x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 d x + \int 6 x d x + \int 36 x^{2} d x

\int 4 d x = 4 x

\int 6 x d x = 3 x^{2}

\int 36 x^{2} d x = 12 x^{3}

= 4 x + 3 x^{2} + 12 x^{3}

Füge eine Konstante zur Lösung hinzu

= 4 x + 3 x^{2} + 12 x^{3} + C

d er i v a t i v e (\frac{( 10 - x )}{4})^{2} + \frac{x ^{2}}{4 π}

\int x sin (10 - x) d x

\int_{6}^{7} t sin (π t) d t

\frac{d}{d x} (lo g_{12} (x^{2} + n x))

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