derivative of ln(x^2-5x+2)

Lösung

\frac{d}{d x} (ln (x^{2} - 5 x + 2))

\frac{2 x - 5}{x ^{2} - 5 x + 2}

Schritte zur Lösung

\frac{d}{d x} (ln (x^{2} - 5 x + 2))

Wende die Kettenregel an:

\frac{1}{x ^{2} - 5 x + 2} \frac{d}{d x} (x^{2} - 5 x + 2)

= \frac{1}{x ^{2} - 5 x + 2} \frac{d}{d x} (x^{2} - 5 x + 2)

\frac{d}{d x} (x^{2} - 5 x + 2) = 2 x - 5

= \frac{1}{x ^{2} - 5 x + 2} (2 x - 5)

Vereinfache

\frac{1}{x ^{2} - 5 x + 2} (2 x - 5) : \frac{2 x - 5}{x ^{2} - 5 x + 2}

= \frac{2 x - 5}{x ^{2} - 5 x + 2}

\int \frac{ln ( 2 )}{x ^{2}} d x

y^{^{'}} = \frac{( 3 t ^{2} - e ^{t} )}{( 2 y - 5 )}, y (0) = 1

n = 1 \sum \infty ln (n + 2)

x \to 2 - lim (ln (x^{2} (3 - x)))

a re a x^{2}, 2 - x^{2}