de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

inverselaplace 6/s+(16)/(s^2+16)

Lösung

inverse laplace transformation

\frac{6}{s} + \frac{16}{s ^{2} + 16}

Lösung

6 H (t) + 4 sin (4 t)

Schritte zur Lösung

L^{- 1} {\frac{6}{s} + \frac{16}{s ^{2} + 16}}

Wende die lineare Eigenschaftder inversen Laplace-Transformation an:

Für Funktionen

f (s), g (s)

und Konstanten

a, b : L^{- 1} {a \cdot f (s) + b \cdot g (s)} = a \cdot L^{- 1} {f (s)} + b \cdot L^{- 1} {g (s)}

= L^{- 1} {\frac{6}{s}} + L^{- 1} {\frac{16}{s ^{2} + 16}}

L^{- 1} {\frac{6}{s}} : 6 H (t)

L^{- 1} {\frac{16}{s ^{2} + 16}} : 4 sin (4 t)

= 6 H (t) + 4 sin (4 t)

Beliebte Beispiele

(d^2y)/(dx^2)=0

\frac{d ^{2} y}{d x ^{2}} = 0

integral from-1 to 1 of e^x-1

\int_{- 1}^{1} e^{x} - 1 d x

limit as x approaches-1+of x^2-3

x \to - 1 + lim (x^{2} - 3)

xydx+(1+y)sqrt(1)-x^2dy=0

x y d x + (1 + y) 1 - x^{2} d y = 0

integral of (6x)/(e^{3x^2)}

\int \frac{6 x}{e ^{3 x^{2}}} d x