taylor 9/x ,1

Lösung

taylor

\frac{9}{x}, 1

9 - 9 (x - 1) + 9 (x - 1)^{2} - 9 (x - 1)^{3} + 9 (x - 1)^{4} + \dots

Schritte zur Lösung

Apply the Taylor Formula

= 9 + \frac{\frac{d}{d x} ( \frac{9}{x} ) ( 1 )}{1 !} (x - 1) + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{9}{x} ) ( 1 )}{2 !} (x - 1)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{9}{x} ) ( 1 )}{3 !} (x - 1)^{3} + \dots

Evaluate Derivatives

= 9 + \frac{- 9}{1 !} (x - 1) + \frac{18}{2 !} (x - 1)^{2} + \frac{- 54}{3 !} (x - 1)^{3} + \frac{216}{4 !} (x - 1)^{4} + \dots

Fasse zusammen

= 9 - 9 (x - 1) + 9 (x - 1)^{2} - 9 (x - 1)^{3} + 9 (x - 1)^{4} + \dots

\int \frac{2 x}{x ^{4} + 25} d x

d er i v a t i v e ln (1 + \frac{3}{x} + \frac{5}{x ^{2}})

\int (x^{4} + 3)^{\frac{3}{2}} x^{3} d x

\frac{\partial}{\partial b} (m x^{b})

\int 8 y d y