derivative of 1-|1-x|

Lösung

\frac{d}{d x} (1 - ∣ 1 - x ∣)

\frac{- x + 1}{∣ - x + 1 ∣}

Schritte zur Lösung

\frac{d}{d x} (1 - ∣ 1 - x ∣)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (∣ 1 - x ∣)

\frac{d}{d x} (1) = 0

\frac{d}{d x} (∣ 1 - x ∣) = - \frac{1 - x}{∣ 1 - x ∣}

= 0 - (- \frac{1 - x}{∣ 1 - x ∣})

Vereinfache

= \frac{- x + 1}{∣ - x + 1 ∣}

\int \frac{x ^{4}}{x} d x

x \to 2 lim (sin (\frac{1}{x - 2}))

x \to \infty lim (\frac{4 x ^{2} + 5 x}{10 + x ^{4}})

3 y^{^{''}} - 12 y = 0

x \to 0 + lim (\frac{1}{x ^{3} - 2 x ^{2}})