y^'=ysin(2x)

Lösung

y^{^{'}} = y sin (2 x)

y = e^{- \frac{1}{2} c o s (2 x) + c_{1}}

Schritte zur Lösung

y^{'} (x) = y sin (2 x)

Solve separable ODE:

y = e^{- \frac{1}{2} c o s (2 x) + c_{1}}

y = e^{- \frac{1}{2} c o s (2 x) + c_{1}}

x \to \infty lim (x (arctan (x) - \frac{π}{2}))

d er i v a t i v e f (x) = (7 x^{6} + 8 x^{3})^{4}

4 y^{^{''}} - 4 y^{^{'}} - 3 y = 0, y (0) = 1, y^{^{'}} (0) = 5

x \to 0 + lim ((cot (x))^{s i n (x)})

x^{2} \frac{d y}{d x} - 2 x y = 3 y^{4}