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人気のある微分積分 >

integral from-1 to 1 of |2-4x|

解

\int_{- 1}^{1} ∣ 2 - 4 x ∣ d x

解

5

解答ステップ

\int_{- 1}^{1} ∣ 2 - 4 x ∣ d x

絶対数を排除する

= \int_{- 1}^{\frac{1}{2}} 2 - 4 x d x + \int_{\frac{1}{2}}^{1} - 2 + 4 x d x

\int_{- 1}^{\frac{1}{2}} 2 - 4 x d x = \frac{9}{2}

\int_{\frac{1}{2}}^{1} - 2 + 4 x d x = \frac{1}{2}

= \frac{9}{2} + \frac{1}{2}

簡素化

\frac{9}{2} + \frac{1}{2} : 5

= 5

グラフ

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