integral from 0 to 1 of x/8

Lösung

\int_{0}^{1} \frac{x}{8} d x

\frac{1}{16}

Dezimale

0.0625

Schritte zur Lösung

\int_{0}^{1} \frac{x}{8} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int_{0}^{1} x d x

Wende die Potenzregel an

= \frac{1}{8} [\frac{x ^{2}}{2}]_{0}^{1}

Berechne die Grenzen:

\frac{1}{2}

= \frac{1}{8} \cdot \frac{1}{2}

Vereinfache

= \frac{1}{16}

\int_{4}^{2} 1

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