integral from-1 to 2 of sqrt(3x+6)

Lösung

\int_{- 1}^{2} 3 x + 6 d x

\frac{14}{3}

Dezimale

8.08290 \dots

Schritte zur Lösung

\int_{- 1}^{2} 3 x + 6 d x

Wende U-Substitution an

= \int_{3}^{12} \frac{u}{3} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int_{3}^{12} u d u

Wende die Potenzregel an

= \frac{1}{3} [\frac{2}{3} u^{\frac{3}{2}}]_{3}^{12}

Berechne die Grenzen:

143

= \frac{1}{3} \cdot 143

Vereinfache

= \frac{14}{3}

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