integral from 1 to 3 of 3x^2-12x+9

Lösung

\int_{1}^{3} 3 x^{2} - 12 x + 9 d x

- 4

Schritte zur Lösung

\int_{1}^{3} 3 x^{2} - 12 x + 9 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 3 x^{2} d x - \int_{1}^{3} 12 x d x + \int_{1}^{3} 9 d x

\int_{1}^{3} 3 x^{2} d x = 26

\int_{1}^{3} 12 x d x = 48

\int_{1}^{3} 9 d x = 18

= 26 - 48 + 18

Vereinfache

= - 4

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