integral from 1 to 3 of 4^{3x}

Lösung

\int_{1}^{3} 4^{3 x} d x

\frac{43680}{ln ( 2 )}

Dezimale

63016.91938 \dots

Schritte zur Lösung

\int_{1}^{3} 4^{3 x} d x

Vereinfache

4^{3 x} : 6 4^{x}

= \int_{1}^{3} 6 4^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{6 4 ^{x}}{ln ( 64 )}]_{1}^{3}

\frac{6 4 ^{x}}{ln ( 64 )} = \frac{2 ^{6 x - 1}}{3 ln ( 2 )}

= [\frac{2 ^{6 x - 1}}{3 ln ( 2 )}]_{1}^{3}

Berechne die Grenzen:

\frac{43680}{ln ( 2 )}

= \frac{43680}{ln ( 2 )}

\int_{3}^{5} sin (I n x) d x

\int_{0}^{4} x + 1 d x

\int_{0}^{2} (6 x - 3) (4 x^{2} + 7) d x

\int_{- 1}^{1} 2 y^{2} - 2 d y

\int_{2}^{7} \frac{14 x}{x ^{2} + 1} d x