integral from-1 to 4 of sqrt(2x+1)

Lösung

\int_{- 1}^{4} 2 x + 1 d x

9 + i \frac{1}{3}

Schritte zur Lösung

\int_{- 1}^{4} 2 x + 1 d x

Wende U-Substitution an

= \int_{- 1}^{9} \frac{u}{2} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{- 1}^{9} u d u

Wende die Potenzregel an

= \frac{1}{2} [\frac{2}{3} u^{\frac{3}{2}}]_{- 1}^{9}

Berechne die Grenzen:

18 + i \frac{2}{3}

= \frac{1}{2} (18 + i \frac{2}{3})

Vereinfache

= 9 + i \frac{1}{3}

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