integral from 0 to 1 of tsin(t)

Lösung

\int_{0}^{1} t sin (t) d t

sin (1) - cos (1)

Dezimale

0.30116 \dots

Schritte zur Lösung

\int_{0}^{1} t sin (t) d t

Wende die partielle Integration an

= [- t cos (t) - \int - cos (t) d t]_{0}^{1}

\int - cos (t) d t = - sin (t)

= [- t cos (t) - (- sin (t))]_{0}^{1}

Vereinfache

= [- t cos (t) + sin (t)]_{0}^{1}

Berechne die Grenzen:

sin (1) - cos (1)

= sin (1) - cos (1)

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\int_{2}^{3} - \frac{3}{x ^{2}} d x