ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある微分積分 >

integral from 0 to 5 of |t^2+2t-15|

解

\int_{0}^{5} t^{2} + 2 t - 15 d t

解

\frac{137}{3}

+1

十進法表記

45.66666 \dots

解答ステップ

\int_{0}^{5} t^{2} + 2 t - 15 d t

絶対数を排除する

= \int_{0}^{3} - t^{2} - 2 t + 15 d t + \int_{3}^{5} t^{2} + 2 t - 15 d t

\int_{0}^{3} - t^{2} - 2 t + 15 d t = 27

\int_{3}^{5} t^{2} + 2 t - 15 d t = \frac{56}{3}

= 27 + \frac{56}{3}

簡素化

27 + \frac{56}{3} : \frac{137}{3}

= \frac{137}{3}

グラフ

人気の例

integral from 0 to 2 of 1/((2-x)^{5/2)}

\int_{0}^{2} \frac{1}{( 2 - x ) ^{\frac{5}{2}}} d x

integral from 2 to 4 of (2x)

\int_{2}^{4} (2 x) d x

integral from-2 to 1 of (2x^3+4x^2-x+3)

\int_{- 2}^{1} (2 x^{3} + 4 x^{2} - x + 3) d x

integral from-2 to 1 of 1/(x^{1/2)}

\int_{- 2}^{1} \frac{1}{x ^{\frac{1}{2}}} d x

integral from 1 to 8 of 1/t

\int_{1}^{8} \frac{1}{t} d t