integral from-1 to 2 of-2x+4

Lösung

\int_{- 1}^{2} - 2 x + 4 d x

9

Schritte zur Lösung

\int_{- 1}^{2} - 2 x + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{2} 2 x d x + \int_{- 1}^{2} 4 d x

\int_{- 1}^{2} 2 x d x = 3

\int_{- 1}^{2} 4 d x = 12

= - 3 + 12

Vereinfache

= 9

\int_{- 5}^{5} 5 d x

\int_{5}^{2} x^{3} d x

\int_{- 1}^{1} (2 - 2 y^{2}) d y

\int_{0}^{π} cos (5 x) d x

\int_{0}^{π} (1 - x) cos (n x) d x