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人気のある微分積分 >

integral from 1 to 2 of (1/x+y)

解

\int_{1}^{2} (\frac{1}{x} + y) d x

解

ln (2) + y

解答ステップ

\int_{1}^{2} \frac{1}{x} + y d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} \frac{1}{x} d x + \int_{1}^{2} y d x

\int_{1}^{2} \frac{1}{x} d x = ln (2)

\int_{1}^{2} y d x = y

= ln (2) + y

人気の例

integral from-1 to 1 of 7/(1+49t^2)

\int_{- 1}^{1} \frac{7}{1 + 49 t ^{2}} d t

integral from-3 to 3 of 3x^4-8x^2

\int_{- 3}^{3} 3 x^{4} - 8 x^{2} d x

integral from-2 to 2 of 1+sqrt(4-x^2)

\int_{- 2}^{2} 1 + 4 - x^{2} d x

integral from 1 to 4 of 5xsqrt(x+1)

\int_{1}^{4} 5 x x + 1 d x

integral from 0 to 10 of arctan(x)

\int_{0}^{10} arctan (x) d x