integral from 2 to 6 of x-1

Lösung

\int_{2}^{6} x - 1 d x

12

Schritte zur Lösung

\int_{2}^{6} x - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{6} x d x - \int_{2}^{6} 1 d x

\int_{2}^{6} x d x = 16

\int_{2}^{6} 1 d x = 4

= 16 - 4

Vereinfache

= 12

\int_{0}^{1} x e^{x} ln (2) d x

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\int_{0}^{2} x 1 + x^{2} d x

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\int_{8}^{\infty} ln (x) d x