integral from 0 to 1 of 1-x^2+1/2 x^4

Lösung

\int_{0}^{1} 1 - x^{2} + \frac{1}{2} x^{4} d x

\frac{23}{30}

Dezimale

0.76666 \dots

Schritte zur Lösung

\int_{0}^{1} 1 - x^{2} + \frac{1}{2} x^{4} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 1 d x - \int_{0}^{1} x^{2} d x + \int_{0}^{1} \frac{1}{2} x^{4} d x

\int_{0}^{1} 1 d x = 1

\int_{0}^{1} x^{2} d x = \frac{1}{3}

\int_{0}^{1} \frac{1}{2} x^{4} d x = \frac{1}{10}

= 1 - \frac{1}{3} + \frac{1}{10}

Vereinfache

1 - \frac{1}{3} + \frac{1}{10} : \frac{23}{30}

= \frac{23}{30}

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