integral from-1 to 1 of (3-x^2)

Lösung

\int_{- 1}^{1} (3 - x^{2}) d x

\frac{16}{3}

Dezimale

5.33333 \dots

Schritte zur Lösung

\int_{- 1}^{1} 3 - x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 3 d x - \int_{- 1}^{1} x^{2} d x

\int_{- 1}^{1} 3 d x = 6

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

= 6 - \frac{2}{3}

Vereinfache

6 - \frac{2}{3} : \frac{16}{3}

= \frac{16}{3}

\int_{- \frac{π}{4}}^{\frac{π}{4}} sin (x) - e^{x} d x

\int_{0}^{4} \frac{x}{1 + x ^{4}} d x

\int_{- 4}^{- 2} - x d x

\int_{2}^{4} (1 - e^{- x}) d x

\int_{0}^{3} 3 x (1 + 3 x^{2})^{2} d x