integral from 0 to pi of 1 (sin(x))

Lösung

\int_{0}^{π} \frac{d}{1} (sin (x)) d x

d \cdot 2

Schritte zur Lösung

\int_{0}^{π} \frac{d}{1} sin (x) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= d \cdot \int_{0}^{π} sin (x) d x

Nutze das gemeinsame Integral :

\int sin (x) d x = - cos (x)

= d [- cos (x)]_{0}^{π}

Berechne die Grenzen:

2

= d \cdot 2

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