integral from 0 to 5 of |x^2-4|

Lösung

\int_{0}^{5} x^{2} - 4 d x

\frac{97}{3}

Dezimale

32.33333 \dots

Schritte zur Lösung

\int_{0}^{5} x^{2} - 4 d x

Entferne die Extremwerte

= \int_{0}^{2} - x^{2} + 4 d x + \int_{2}^{5} x^{2} - 4 d x

\int_{0}^{2} - x^{2} + 4 d x = \frac{16}{3}

\int_{2}^{5} x^{2} - 4 d x = 27

= \frac{16}{3} + 27

Vereinfache

\frac{16}{3} + 27 : \frac{97}{3}

= \frac{97}{3}

\int_{- 1}^{1} ∣ ln (x + 1.5) ∣^{3} d x

\int_{1}^{4} (x)^{2} d x

\int_{0}^{2} (t + 2)^{2} - 3 d t

\int_{0}^{1} (\frac{y}{1 + x y}) d x

\int_{0}^{3} (x + 5) d x