integral from-1/2 to 1 of (sin(x^2))/x

解

\int_{- \frac{1}{2}}^{1} \frac{sin ( x ^{2} )}{x} d x

- 0.5 Si (\frac{1}{4}) + 0.4730415352

解答ステップ

\int_{- \frac{1}{2}}^{1} \frac{sin ( x ^{2} )}{x} d x

未定義の (特異) 点を求める:

x = 0

存在する場合は

b, a < b < c, f (b) =

未定義

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- \frac{1}{2}}^{0} \frac{sin ( x ^{2} )}{x} d x + \int_{0}^{1} \frac{sin ( x ^{2} )}{x} d x

\int_{- \frac{1}{2}}^{0} \frac{sin ( x ^{2} )}{x} d x = - \frac{1}{2} Si (\frac{1}{4})

\int_{0}^{1} \frac{sin ( x ^{2} )}{x} d x = 0.4730415352

= - \frac{1}{2} Si (\frac{1}{4}) + 0.4730415352

簡素化

= - 0.5 Si (\frac{1}{4}) + 0.4730415352